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Unformatted text preview: Solutions Problem Set # 1 Ch. 33 Conceptual Questions 33.]. (”Thespheteisnoteﬂeendbymem Glueisnotnupetic. (”Mimmmkheemhghummmmeimmfmmmmw
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materiallouoﬂhem 33.3. Yes, if both cylinders are magnets they will repel if one of them is turned 180°. If only one cylinder is a
magnet, then they will still attract after one of them is turned around. Ch. 33 Problems 335. Md: mmﬂtﬂisdﬂoﬂm‘uywm
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uh 33.14. Model: Assume the wires are inﬁnitely long.
Visualize: Please refer to Figure EX33.14.
Solve: The magnetic field strength at point a is “o M d , out of page) + ( 21rd , into page) top bottom 1 \ _ —7 (—_—
) J'(2"10 Tm/A)(10A)l2.0x10'2m 6.0x10'2mJ _ (4.0 + 2.0 cm => Em = (6.7 x10'5 T, out ofpage) At points b and c, 33.43. Model: Assume that the wires are infinitely long and that the magnetic field is due to currents in both the
wires. Visualize: Point 1 is a distance dl away from the two wires and point 2 is a distant d2 away from the two wires.
A right triangle with a 75° degree angle is formed by a straight line from point 1 to the intersection and a line from point 1 that is perpendicular to the wire. Likewise, point 2 makes a 15° right triangle. d. = (4.0 cm) sin75" Solve: First we determine the distances dl and d2 of the points from the two wires: 1 = (4.0 cm)sin75° = 3.86 cm = 0.0386
2 = (4.0 cm)sin15° = 1.04 cm = 0.0104 At point 1, the fields from both the wires point up and hence add. The total field is
) (4 x10'7 T m/A)(5.0 A) = — = 5.2 x10—5
0.0386 In In vector form, '= (5.2 x 10'5 T, out of page). Using the righthand rule at point 2, the fields are in opposite directions but equal in magnitude. So, I'. 33.53. Model: The magnetic field is that of a current in the wire.
Visualize: Please refer to Figure P3353. Solve: As given in Equation 33.6 for a current carrying small segment the BiotSavart law is For the straight sections, “because both and point along the same line. That is not the case with the
curved section over which ‘ where we used '_ = RA is R d!‘ for the small arc length As. Integrating to obtain the total magnetic field at the center of the semicircle, ...
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 Fall '08
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