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Unformatted text preview: HOMEWORK CHAPTER 1 1. REASONING AND SOLUTION a. The SI unit for x is m. The SI units for the quantity vt are m s (s) = m m s (s) m F H G I K J = Therefore, the units on the left hand side of the equation are consistent with the units on the right hand side. b. As described in part a , the SI units for the quantities x and vt are both m. The SI units for the quantity 1 2 at 2 are m s (s ) m 2 2 F H G I K J = Therefore, the units on the left hand side of the equation are consistent with the units on the right hand side. c. The SI unit for v is m/s. The SI unit for the quantity at is m s (s) m s 2 F H G I K J = Therefore, the units on the left hand side of the equation are consistent with the units on the right hand side. d. As described in part c , the SI units of the quantities v and at are both m/s. The SI unit of the quantity 1 2 at 3 is m s (s ) m s 2 3 F H G I K J = ⋅ Thus, the units on the left hand side are not consistent with the units on the right hand side. In fact, the right hand side is not a valid operation because it is not possible to add physical quantities that have different units. e. The SI unit for the quantity v 3 is m 3 /s 3 . The SI unit for the quantity 2 ax 3 is m s (m ) m s 2 2 3 2 F H G I K J = Therefore, the units on the left hand side of the equation are not consistent with the units on the right hand side. f. The SI unit for the quantity t is s. The SI unit for the quantity 2 x a is m (m / s ) m s m s s 2 2 2 = F H G I K J = = Therefore, the units on the left hand side of the equation are consistent with the units on the right hand side. 11. REASONING AND SOLUTION One can arrive back at the starting point after making eight consecutive displacements that add to zero only if one traverses three of the edges on one face and three edges on the opposite face (six displacements; the...
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 Spring '09
 DARICI
 Pythagorean Theorem, Work, Right triangle, Hypotenuse

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