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Unformatted text preview: A) CH 4 B) NH 4 + C) BCl 3 D) -OH __ pK a = -7 5) Identify which is the pK a for HCl (a very strong acid). A) pK a = 12 A) pK a = -7 A) pK a = 35 A) pK a = 50 ________ 6) Extra Credit: (2 points) Given the pK a s for the following acids which direction does the reaction proceed. (Circle the correct arrow) ANSWER: Reaction proceeds from right to left A) B) C) D) A) B) C) D) Br-HBr pK a = -9 CH 3 OH 2 + pK a = -2.5 CH 3 OH 2 + HBr + CH 3 OH +...
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This note was uploaded on 12/22/2011 for the course CHEM 3053 taught by Professor Laurashirtcliff during the Fall '11 term at Oklahoma State.
- Fall '11
- Organic chemistry