10Q4 - ~v =-2 ~ j + 2 ~ k at the point (1,1,-1). 4. (5 pts)...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Name: Quiz 4 1. Find the partial derivatives: (a) (2 pts) P ( x, y ) = 3 x 5 - 2 xy + x 4 - y ; P x ( x, y ) = · · · (b) (2 pts) f ( x, y ) = y ln ± x 2 y ! ; f y ( x, y ) = · · · (c) (2 pts) g ( u, v ) = uv 2 2 u 2 + 3 v ; g u ( u, v ) = 2. (4 pts) Find an equation of the tangent plane to the graph of the function f ( x, y ) = cos x +3 y 2 at the point(0,1,4).
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
3. (5 pts) Find the directional derivative of the function f ( x, y, z ) = 3 x 2 z + xyz 2 in the direction of the vector
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ~v =-2 ~ j + 2 ~ k at the point (1,1,-1). 4. (5 pts) (a) Suppose the function f ( x, y ) has continuous partial derivatives. Use the chain rule to write a formula for the derivative of the function F ( t ) = f (5 t 3 , t 2 ) . (b) If f x (5 , 1) =-2 , f y (5 , 1) = 3 , find the derivative F (1) ....
View Full Document

This note was uploaded on 12/23/2011 for the course MATHEMATIC MATH 102 taught by Professor Plamendjakov during the Spring '10 term at Sabancı University.

Page1 / 2

10Q4 - ~v =-2 ~ j + 2 ~ k at the point (1,1,-1). 4. (5 pts)...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online