ee20-hw03-f10sol - tered on the active point for the dirac...

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HW 3.2 (a) In this part, we recognize that the output will simply be the convolution of two boxes of magnitude 1 and width 1. We know to use convolution because even if we did somehow find the frequency response of our system, our input signal is not periodic. As we discussed in lecture, the convolution of two equally wide boxes will give us the triangular figure shown below. (b) For this part, we are convolving of two boxes of magnitude 1, but dif- fering widths. This will give us the saturated triangular figure shown below. (c) Since convolution with the dirac delta just makes two copies of x cen-
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Unformatted text preview: tered on the active point for the dirac delta, we get by inspection the following simple gure. Note the maximum magnitude is when the two copies are added (so it is 2, not 1). (d) In this case, we simply have an innite number of copies of our box, centered on the active point for each delta. 1-3-2-1 1 2 3 4 5 6 0.2 0.4 0.6 0.8 1 t y(t) Figure 1: y ( n ) 2-3-2-1 1 2 3 4 5 6 0.2 0.4 0.6 0.8 1 t y(t) Figure 2: y ( n ) 3-1-0.5 0.5 1 1.5 2 0.5 1 1.5 2 t y(t) Figure 3: y ( n ) 4-10-8-6-4-2 2 4 6 8 10 0.5 1 t y(t) Figure 4: y ( n ) 5...
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This note was uploaded on 12/24/2011 for the course ELECTRICAL 20 taught by Professor Babak during the Spring '11 term at University of California, Berkeley.

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ee20-hw03-f10sol - tered on the active point for the dirac...

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