Assignment-1.Spring_2006.solution

# Assignment-1.Spring_2006.solution - CIVL 232 Design of...

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1 CIVL 232 Design of Structural Concrete Solution to Assignment 1 1. Solution (a) Two principal types of limited state: Ultimate limit state : The whole structure or its components should not collapse, overturn or buckle when subjected to design loads. Serviceability limit state : The structure should not become unfit for use due to excessive deflection, cracking, vibration and so on. (b) γ m takes the account of: i. Uncertainties in strength ii. Uncertainties in the accuracy of the methods of analysis γ f takes the account of: i. Possible increase in loads ii. Inaccurate assessment of the effects of loads iii. Unforeseen stress redistribution iv. Constructional inaccuracies 2. Solution (a) The weight of foundation at A can be determined by considering the following load arrangement: Take moment about B , kN 1 . 69 0 2 192 1 2 2 . 46 4 2 4 25 = = × × × × + × × A R A kN/m 25 0 . 1 = k G kN/m 2 . 46 6 . 1 4 . 1 = + k k Q G kN 192 6 . 1 = k Q 4 m 2 m A B

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2 (b) Loading case 1 : 1.4G k + 1.6 Q k on span AB and 1.0 G k on span BC The reaction force at A = 79.9 kN (upward) The reaction force at B = 154.9 kN (upward) The maximum moment location = m 73 . 1 2 . 46 9 . 79 = Consider the free body from A to the 1.73 m from A, kNm 11 . 69 0 2 73 . 1 2 . 46 73 . 1 9 . 79 max max 2 = = + × + × M M Loading case 2 : 1.4G k + 1.6 Q k on span AB and 1.0 G k on span BC The reaction force at A = 69 kN (downward) The reaction force at B = 64.5 kN (upward) 4m 2m A B 1.4 1.6 46.2 kN/m kk GQ += 1.0 25 kN/m k G = Loading case 1 m kN G k / 25 1 = m kN Q G k k / 2 . 46 6 . 1 4 . 1 = + kN Q k 192 6 . 1
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Assignment-1.Spring_2006.solution - CIVL 232 Design of...

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