Assignment-4.CIVL232.Spring_2006.solution

Assignment-4.CIVL232 - CIVL 23 Design of Structural Concrete Spring 2005 Solutions of Assignment 4 Question 4.1(a Given N =3000 kN M = 800 kN-m N

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1 CIVL 23 Design of Structural Concrete Spring 2005 Solutions of Assignment 4 Question 4.1 (a) Given N =3000 kN, M = 800 kN-m, 3 3000 10 14.29 350 600 N bh × == × 6 22 800 10 6.35 350 600 M bh × × From BS 8110: Part 3: Chart No. 39 (for columns with f cu = 40 N/mm 2 , f y = 460 N/mm 2 , d / h = 0.9, and symmetrical arrangement of steel reinforcement), 100 3.4 sc A bh = Hence, A sc = 3.4 bh /100 = 3.4 × 350 × 600/100 = 7140 mm 2 A sc /2 = 3570 mm 2 . (b) Given N =1800 kN and e = 500 mm, M = N e = 1800 × 500 × 10 -3 = 900 kN-m 3 1800 10 8.57 350 600 N bh × × 6 900 10 7.14 350 600 M bh × × From BS 8110: Part 3: Chart No. 39, 100 3.1 sc A bh = < 3.4 Thus, the section has sufficient capacity to resist the design axial load.
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2 Question 4.2 Let h = d + 50 = 550 + 50 = 600 mm The self-weight of the beam = 2400 × 0.3 × 0.6 = 4.3 kN/m (a) Q k = 0 Design load = 1.4 × (10+4.3) × 6 = 120.3 kN Shear force at the face of the support 3 22 120.3 3000 230 2 57.8 kN 2 3000 57.8 10 0.35 N/mm 0.8 4 N/mm . OK 300 550 cu V V vf bd = × == = < = × Shear force at the critical section (distance d from the face of the support), 3 2 120.3 3000 230 / 2 540 47.0 kN 2 3000 47.0 10 0.29 N/mm 300 540 xx V V v bd −− = × = × With 100 A s /( bd ) = 100 × 1960/(300 × 550) = 1.19 and f cu = 30 N/mm 2 , from Table 3.8 BS 8110: Part 1 (the Notes p.114) the design concrete shear stress
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This note was uploaded on 12/24/2011 for the course CIVL 232 taught by Professor Jskuang during the Spring '06 term at HKUST.

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Assignment-4.CIVL232 - CIVL 23 Design of Structural Concrete Spring 2005 Solutions of Assignment 4 Question 4.1(a Given N =3000 kN M = 800 kN-m N

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