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Unformatted text preview: he same for each set of bars. This gives
As sv fy = Asv (x1 + y1) fyv
or ⎛x y ⎞
As f y = Asv f yv ⎜ 1 + 1 ⎟
⎜s s ⎟
⎝v ∴ The torsional longitudinal bars required
As ≥ Asv f yv
(x1 + y1 )
sv f y (3.33) 144 o Note that reinforcement in beams includes the reinforcement required for flexure and shear plus that required for torsion.
o To ensure the proper action of the links, longitudinal bars must be provided evenly distributed round the inside perimeter of the
links, as shown in Fig. 3.4-4. Fig. 3.4-4 Longitudinal bars evenly distributed round the links • Reinforcement...
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This note was uploaded on 12/24/2011 for the course CIVL 232 taught by Professor Jskuang during the Spring '06 term at HKUST.
- Spring '06