Chapter_15

Chapter_15 - Chapter 15 Kinetics and Equilibrium 2 NO 2 (g)...

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Unformatted text preview: Chapter 15 Kinetics and Equilibrium 2 NO 2 (g) 2 4 ( 29 Both forward and reverse reactions elementary reactions. R f = k f [NO 2 ] 2 and R r = k r [N 2 O 4 ] 1 At equilibrium forward & reverse rates equal. R f (equilibrium) = R r (equilibrium) k f [NO 2 ] 2 eq = k r [N 2 O 4 ] 1 eq k f /k r = [N 2 O 4 ] 1 eq /[NO 2 ] 2 eq = K eq Equilibrium Constants Consider at e q u i l i b r i u m : N 2 + 3 H 2 2 NH 3 (Haber Reaction) N 2 + H 2 + H 2 + H 2 NH 3 + NH 3 [N 2 ][H 2 ][H 2 ][H 2 ] [NH 3 ][NH 3 ] K eq = [NH 3 ] 2 = [N 2 ][H 2 ] 3 equil. 15.31 | 2 ( 29 + 2 2 ( 29 2 ( 29 + 2 2 ( 29 I 0.10 M 0.05 M 0 M 0.10 M D-2x-2x +1x +2x E 0.10-2x 0.05-2x x 0.10+2x A 0.062 M (a) Calculate [H 2 ] eq , [N 2 ] eq , and [H 2 O] eq . (b) Calculate K c . Reaction (Completion) Quotients If not at equilibrium then [PROD]/[REAC] K eq !!...
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Chapter_15 - Chapter 15 Kinetics and Equilibrium 2 NO 2 (g)...

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