EEL3105_MT2_Solution

Ctraceofamatrixisthesumofeigenvaluestherefore trace ba

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Unformatted text preview: 2, 4, ‐2, and 0. [In the other version, the eigenvalues of BA are 1, 2, ‐1, 0.] b. Since determinant of a matrix is the product of eigenvalues, we must have det( BA) 0. c. Trace of a matrix is the sum of eigenvalues. Therefore, trace( BA) 4. (For the other version trace(BA) =2.) d. No BA is singular since its determinant=0. 5. By definition, 1 0 0 AA 0 1 0 . 0 0 1 1 a Now if the vector b is the first column vector of A‐1, we must have 1 1 3 5 a 1 2 4 6 b 0 3 5 8 1 0 We get the following simultaneous equations for a and b: a 3b 5 1 2a...
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