Lecture%208-2 - Measures of Relative Standing Consider the...

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Measures of Relative Standing: Consider the following scenario: In Sec. 1 of a statistic course, Jack scored 86 out of 100 in Exam 1, where the mean and the standard deviation of the class were g1876g1191= 80 and s= 4. In Sec. 2 of the same course, Jill scored 15 out of 20 in Exam 1, where the mean and the standard deviation of the class were g1876g1191= 12 and s= 1.5. Can we say who did better?
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Recall the example: In Sec. 1 of a statistic course, Jack scored 86 out of 100 in Exam 1, where the mean and the standard deviation of the class were g1876g1191= 80 and s= 4. In Sec. 2 of the same course, Jill scored 15 out of 20 in Exam 1, where the mean and the standard deviation of the class were g1876g1191= 12 and s= 1.5. z-score of Jack is z = g3051 g2879 g3051g1191g3046= g2876g2874g2879g2876g2868g2872= 6/4 = 1.5 Jack’s score 86 is ``1.5 standard deviation’’ , i.e., (1.5)*4 above the mean g1876g1191= 80 z-score of Jill is z = g3051 g2879 g3051g1191g3046= g2869g2873g2879g2869g2870g2869.g2873=

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