E_-_102_F11_Notes

# 3145jmolk t temperatureink f

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ):    F = (6.022137 x 1023 mol‐1) (1.6021773 x 10‐19 C)        = 96 485.31 C / mol    Electric current (I) is the amount of charge (Q) flowing through circuit per unit of time (t):          The number of moles of electrons that flow through a circuit can be calculated by the  equation:   It total ch arg e pas sin g thru the circuit   n= = F ch arg e of a mole of electrons ChE102 Fall 2011 Class Notes ‐ Electrochemistry  €               E ‐5   Application of Faraday’s Law  • From the number of moles passing through the circuit  • We can calculate the mass of a given substance being produced or consumed at an  electrode.  • For the previous Cu|Cu2+||Ag+|Ag cell, for each mole of electrons that passes through  the circuit:  • ½ mole Cu (s) is oxidized = (63.5 g/mol) / (2 mol) = _________ g of Cu (s) are  dissolved at the anode.  • 1 mole of Ag+ is reduced = _______ g of Ag (s) are ...
View Full Document

Ask a homework question - tutors are online