Unit 01-4 Lecture 2 - Given - No! E + must be perpendicular...

Info iconThis preview shows pages 1–10. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Electric Fields In and Near Conductors in Electrostatic Equilibrium An electric conductor has some mobile charges that are free to move in the conductor and along its surfaces. Electrostatic equilibrium means that charges are in static equilibrium . This means that there must be no net electric force on any mobile charge. 1. 0 E in a conductor in electrostatic equilibrium. If E was 0 in the conductor, then a mobile charge q would be acted on by a net electric force 0 elec E q F , and would therefore have a nonzero acceleration and would therefore not be in equilibrium. No! q elec F E 2. Any isolated (separated) charge on a conductor in electrostatic equilibrium can only be on its surfaces (outer and/or inner—if hollow). If isolated (separated) charges were resent in the conductor then electric field present in the conductor, then electric field lines would start or end on each charge, and E would 0 in there. 3. E just outside the surface of a conductor in electrostatic equilibrium
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: No! E + must be perpendicular ( ) to the surface. If E had a component parallel ( ) to the surface ( | | E ), then a mobile charge q on the surface would be cted on by a force and No! q elec F E acted on by a force | | elec E q F , and would therefore have a nonzero acceleration and would therefore not be in equilibrium. Mobile electric charges in/on the conductor redistribute until these conditions for electrostatic equilibrium are met. || E (A) (B) each of the abo e cases the In each of the above cases, the conductors have charges that are equal in magnitude but opposite in sign. In each case, the positively charged conductor is the one on the ght right. Draw electric field lines for each case. Which best describes the path of the proton between the two plates with equal charge magnitudes but pposite signs? opposite signs? A. B. C. D. E....
View Full Document

Page1 / 10

Unit 01-4 Lecture 2 - Given - No! E + must be perpendicular...

This preview shows document pages 1 - 10. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online