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Unformatted text preview: against t is linear with slope d /d( t) = ult . (4c v /3d 2 ); thus c v = 3d 2 /4t x From Figure Q4.5, t x = 5.95 min 0.5 t x = 35.4 minutes drainage path length d = 10 mm (half the nominal sample height) hence c v = 10 2 mm 2 /35.4 minute = 2.12 mm 2 /minute divide by 60 106 to convert mm 2 /minute to m 2 /second c v = 3.53 108 m 2 /s...
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This note was uploaded on 12/28/2011 for the course CHM 4302 taught by Professor Stuartchalk during the Fall '11 term at UNF.
 Fall '11
 StuartChalk
 Analytical Chemistry

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