Analytical Chem Soil HW Solutions 71

Analytical Chem Soil HW Solutions 71 - relationships...

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71 [University of London 2nd year BEng (Civil Engineering) examination, Queen Mary and Westfield College] Q5.5 Solution q is the deviator stress = σ 1 3 = ' 1 - ' 3 p is the average total stress = 1 / 3 ( 1 + 2 + 3 ) p' is the average effective stress = p – u q is given by the ram load Q divided by the current sample area A In an undrained test the total volume V t is constant = A 0 .h 0 = A.h = A.h 0 .(1 – ε ax ) where ax is the axial strain Δ h/h 0 , hence A = A 0 /(1 – ax ) and q = Q.(1 – ax )/A 0 u is the pore water pressure (measured); 2 = 3 = cell pressure CP (measured); and 1 = cell pressure CP + q, so p = CP + q/3 The processed data (to obtain p and p' from the values of q and u given, according to the
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Unformatted text preview: relationships derived above) are given in the table below. q, kPa 0 13.8 27.5 41.3 53.0 59.5 63.0 u, kPa 0 4.6 9.2 13.8 33.6 48.0 59.3 p, kPa 100 104.6 109.2 113.8 117.7 119.8 121.0 p', kPa 100 100.0 100.0 100.0 84.1 71.8 61.7 Graphs of q against p and p' are plotted in Figure Q5.5. Figure Q5.5: q against p and p' OYC is the effective stress path followed in an undrained test. Along OY, the soil is within the initial yield locus and therefore deforms elastically (in the sense that volume change can only occur if there is a change in effective stress) at p' = constant. At Y, the soil yields and...
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This note was uploaded on 12/28/2011 for the course CHM 4302 taught by Professor Stuartchalk during the Fall '11 term at UNF.

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