Unformatted text preview: t /V s = 150796/43074 = 3.501 Hence we can calculate the specific volume during the consolidation stage of the test as v = 3.501 – Δ V t /V s as in the table below: CP, kPa (= p') 25 50 75 100 150 174 u, kPa 0 0 0 0 0 0 V t , cm 3 0 22.4 34.47 43.08 56.01 60.31 ln p' (p' in kPa) 3.219 3.912 4.317 4.605 5.011 5.159 v 3.501 2.981 2.701 2.501 2.201 2.101 During the shear test, p' = CP – u + q/3 and the cell pressure CP = 274 kPa. Hence CP, kPa 274 274 274 274 274 274 u, kPa 100 104 114 132 162 189 q, kPa 0 10 20 30 40 45 p', kPa 174 173.3 166.7 152.0 125.3 100.0 The state paths followed in terms of v against lnp' and q against p' are plotted in Figures Q5.7 a and b....
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 Fall '11
 StuartChalk
 Analytical Chemistry, total volume Vt, cell pressure CP

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