Unformatted text preview: compression line and the slope Î» is given by Î» = -Î” v/ ln p' = (3.501 â€“ 2.101) Ã· (5.159 â€“ 3.219) = 0.722 from the data for the isotropic compression of sample A. We know that the end point of test A lies on the critical state line on the graph of v against lnp' at p' = 100 kPa, and that for a drained test on sample B p' at the critical state would be 164.7 kPa. Hence the change in specific volume during a drained shear test on sample B would be v = 0.722 (ln p') = 0.722 Ã— (ln164.7 â€“ ln100) = 0.360 To find the actual volume of water expelled, we must multiply this by the volume of solids V s (because V t = V s . v) to give...
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- Fall '11
- Analytical Chemistry, kPa, lnp