110314 - Physics 122 3/14/11 3/14/11 Physics 122 1 3/14/11...

Info iconThis preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Physics 122 3/14/11 Prof. E. F. Redish 1 3/14/11 1 Physics 122 3/14/11 2 Physics 122 3/14/11 4 Physics 122
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Physics 122 3/14/11 Prof. E. F. Redish 2 3/14/11 3/14/11 6 Physics 122 3/14/11 7 Physics 122 v 0 = T μ
Background image of page 2
Physics 122 3/14/11 Prof. E. F. Redish 3 3/14/11 8 Physics 122 y ( x ,0) = A sin( kx ) y ( x , t ) = A sin[ k ( x ± v 0 t )] 3/14/11 9 Physics 122 y ( x , t ) = A sin( kx ± ² t ) k = 2 ³ ´ = 2 T 3/14/11 10 Physics 122 ± = v 0 T = v 0 1 f ² ³ ´ µ · or f = v 0 2 k ² ³ ´ µ · = v 0 2 ¸ ² ³ ´ µ · or k = v 0
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Physics 122 3/14/11 Prof. E. F. Redish 4 3/14/11 11 Physics 122 y = A sin( kx 1 ± ² t ) + A sin( kx 2 ± t ) y = A sin( ³ 1 ± t ) + A sin( 2 ± t ) x 1 x 2 3/14/11 12 Physics 122 3/14/11 13 Physics 122 y = A sin( kx 1 ± t ) + A sin( kx 2 ± t ) y = A sin( 1 ± t ) + A sin( 2 ± t ) ± 1 ² 2 1 ² 2 = kx 1 ² kx 2 = kx 1 ² x 2 (29 = k ³ D = 2 ´ ³ D µ
Background image of page 4
Physics 122 3/14/11 Prof. E. F. Redish 5 3/29/10 14 Physics 122 t y 3/29/10 15 Physics 122 4 ± 3 ± 3/29/10 16 Physics 122 3.5 ± 4 ±
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Physics 122 3/14/11 Prof. E. F. Redish
Background image of page 6
Background image of page 7
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 7

110314 - Physics 122 3/14/11 3/14/11 Physics 122 1 3/14/11...

This preview shows document pages 1 - 7. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online