Answer Week 4 - (W)y=145xlem Answers —- Week 4 In an E -...

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Unformatted text preview: (W)y=145xlem Answers —- Week 4 In an E - field a stationary charge q experiences a Force £5 = q E . Therefore, attach q to the Force measuring device which can measure both magnitude and ' direction of Force. If in some region q experiences a force you know that it is locath in an E — field. ‘ Ex ,5.‘ Eth r2 E0) = Q + EM y—components cancel V > W x —components add ‘ a —2k Lines 7 ' E: eq 2 _ keqd )3 a. d2 2 % y2 +— 2 +5]— 4 y 4 y>>d y Dipole moment 13 = 610’)? kep p j ' minim Seem-=— ;=— 1 :3. a; 0 ft y 47r so y 5 -~ WW? (0 q=9x10”m/s252 (ii) K =107m/sfc+l.35x105m/sfz (iii) 1:: 0.15m)? +1v_01x1o-3m.:;~:;>»5’>’ Put Q at center of a sphere at r 91 0. E = Q 2 p 471780 r FLUX THROUGH SPHERICAL SURFACE (DE = = "Q— C 50 ., Mfiwwmmr'g’ All the E field lines must head to infinity so same total flux must go through any closed surface surrounding Q. Total flux is zero. 7 We DONOT KNOW E - field at any point on surface. 4-11 ON THE SURFACE OF CONDUCTOR, UNDER STATIONARY CONDIITONS, — CHARGES MUST BE AT REST SO 5 - field at any point inside conductor must be zero. -13 0' = 9 x 10'10 Chm2 .1; l .1; | —175 In a conservative force work done is Independent of the path. It is determined only by the end points. WeightEG = —M g j» is a conservative force. ' ...
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Answer Week 4 - (W)y=145xlem Answers —- Week 4 In an E -...

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