ay45c4-page5

ay45c4-page5 - we get  (M1 M2)R = 0 or R = 0 Thus the...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: we get   (M1 + M2)R = 0 or R = 0 : Thus, the location of the center of mass of the system is unaccelerated, since there is no external force on the system. It follows that the center of mass moves at a constant velocity: R _ R  ddt = v = constant R = R0 + v 0 t : This relation expresses the \Conservation of Linear Momentum." R0 and V 0 are the rst 6 \constants of motion." The next logical thing to do is to change to center-of-mass coordinates r01; r02, that is, to coordinates relative to the center of mass. M1 CoM r1 ′ r1 r2 ′ M2 R r2 O The relevant relationships are: r1 r2 R = = = R + r01 R + r02 R0 + v0t : Substituting these into the equations of motion, we get  M r0 = GM1 M2 (r0 r0 ) 11 jr01 r02j3 64 1 2 ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online