Unformatted text preview: P mass m F1
ψ 2 r 60 A
M1 60 O R M2 CoM
pR B (1− p)R We want to see that F 1 + F 2 exactly balances the centrifugal term mr!2.
The magnitudes of F 1 and F 2 are F1 = GmM1 = Gm(1R2 p)M
R2 F2 = GmM2 = GmpM
R2 where p M2=M1 and M = M1 + M2. So the condition for force balance
perpendicular to r is
F1 sin 1 = F2 sin 2 :
Apply the Law of Sines to the triangle AOP, p sin 60 = 3=2 = sin 1 :
View Full Document
This note was uploaded on 12/29/2011 for the course AST 350 taught by Professor Dion during the Fall '09 term at SUNY Stony Brook.
- Fall '09