{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Respiration160-page8 - (with its electrons(originally part...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Cell Respiration - 8 Oxidation of Pyruvate to Acetyl The two Pyruvate molecules from the original glucose are transported into the inner matrix of the mitochondria by facilitated diffusion Each pyruvate is oxidized releasing H + to reduce NAD + to NADH CO 2 is removed producing Acetyl (A 2-carbon compound) Acetyl combines with Coenzyme A to form Acetyl-CoA, which can enter the Krebs cycle. For one glucose molecule (two pyruvate molecules), we obtain: 2 CO 2 2 NADH 2 Acetyl C0-A Note: When the level of ATP is high in a cell, the cell can convert acetyl-CoA into lipid molecules that can be stored for later energy use. This is one way that excess calories, no matter the nutrient source, are converted to fat. The Krebs Cycle The Krebs cycle is a means to remove energy rich H
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: + (with its electrons) (originally part of the glucose molecule) that can subsequently be used to generate ATP in electron transport via chemiosmosis. The leftover carbon is given off as CO 2 . Essentially, the acids of the Krebs cycle are substances that under the right conditions (i.e., The Krebs Cycle) can be oxidized (That is donate H + with its electrons). For each glucose molecule, two ATP are produced in the Krebs cycle by substrate-level phosphorylation, one for each acetyl Co-A molecule that enters the Krebs cycle. (Recall that the glucose molecule has already gone through glycolysis and has been converted to two molecules of Pyruvate in the cytoplasm prior to starting the Krebs cycle.)...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern