M119L11to12-page5

# M119L11to12-page5 - 4 Ks 3 Ks ≈ 0.000362 Think About It...

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(Lesson 11: Multiplication Rule; 4-4) 4.18 Solution to Example 3 Because we are drawing cards without replacement, previous draws affect later draws, and the draws are dependent. P A-1st and K-2nd and K-3rd ( ) = P A-1st ( ) P K-2nd A-1st ( ) P K-3rd A-1st and K-2nd ( ) = 4 52 4 51 3 50 51 cards, 50 cards,
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Unformatted text preview: 4 Ks 3 Ks ≈ 0.000362 Think About It: Why is this probability for the AKK sequence lower than the one we found for Example 2, when we were drawing with replacement? Also, why is P K-2nd A-1st ( ) in this example higher than P K-2nd ( ) in Example 2?...
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## This note was uploaded on 12/29/2011 for the course MATH 119 taught by Professor Kim during the Fall '09 term at SUNY Stony Brook.

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