Precalc0105to0107-page28

Precalc0105to0107-page28 - (Section 1.6: Combining...

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(Section 1.6: Combining Functions) 1.6.16 • Find the domain. We may rewrite V as fr () , or even Vr . r , the base radius of the water cone, can be anything from 0 meters (a degenerate case corresponding to no water at all) to 5 meters, the base radius of the tank (corresponding to a full tank). If V = , then Dom f = 0, 5 ± ² ³ ´ . Units (m) aren’t written here. Answer: V = 2 3 ± r 3 on 0, 5 ± ² ³ ´ . • Note: We can also express V as a function of h on 0,10 ± ² ³ ´ . We solve the constraint equation for r and express r as a function of h . h = 2 r r = h 2 We then make the substitution r = h 2 ± ² ³ ´ µ into V = 1 3 r 2 h . V = 1 3 h 2 ² ³ ´ µ · 2 h V = 1 3 h
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This document was uploaded on 12/29/2011.

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