Precalc0110to0111-page23

Precalc0110to0111-page23 - slope of the desired tangent...

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(Section 1.11: Limits and Derivatives in Calculus) 1.11.12 PART E: EQUATIONS OF TANGENT LINES Example 3 (Profit; Revisiting Example 2) Again, Px () = ± x 2 + 200 x ± 5000 . Find Slope-Intercept and Point-Slope Forms of the equation of the tangent line to the graph of y = Px () at the point 60, P 60 () () . (Review Section 0.14 on these forms.) § Solution • Find P 60 () , the y -coordinate of the desired point. P 60 () = ± 60 () 2 + 200 60 () ± 5000 = 3400 dollars () • Find ± P 60 () , the
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Unformatted text preview: slope of the desired tangent line. In Part D, we showed (three times) that: ± P 60 ( ) = 80 dollars widget ² ³ ´ µ ¶ · • Find a Point-Slope Form of the equation of the tangent line. y ± y 1 = m x ± x 1 ( ) y ± 3400 = 80 x ± 60 ( ) • Find the Slope-Intercept Form of the equation of the tangent line. y = 80 x ± 1400 • Note: Some sources would use P instead of y as the dependent variable. §...
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