Unformatted text preview: x = sin x cos x and cot x = cos x sin x Pythagorean Identities sin 2 x + cos 2 x = 1 1 + cot 2 x = csc 2 x tan 2 x + 1 = sec 2 x Tip : The 2 nd and 3 rd IDs can be obtained by dividing both sides of the 1 st ID by sin 2 x and cos 2 x , respectively. Tip : The squares of csc x and sec x , which have the “Up-U, Down-U” graphs, are all alone on the right sides of the last two IDs. They can never be 0 in value. (Why is that? Look at the left sides.)...
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This note was uploaded on 12/29/2011 for the course MATH 150 taught by Professor Sturst during the Fall '10 term at SUNY Stony Brook.
- Fall '10