Unformatted text preview: sin 3 = 3 2 , so 3 will be the reference angle for our solutions for . Since ± 3 2 is a negative sin value, we want brothers of 3 in Quadrants III and IV....
View Full Document
This note was uploaded on 12/29/2011 for the course MATH 150 taught by Professor Sturst during the Fall '10 term at SUNY Stony Brook.
- Fall '10