CalcNotes0103-page8

CalcNotes0103-page8 - (Chapter 1 Review 1.42 Our solutions...

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(Chapter 1: Review) 1.42 Our solutions for ± are: = 4 ² 3 + 2 n ,o r = 5 3 + 2 nn integer () From this point on, it is a matter of Algebra. To find our solutions for x , replace with 4 x , and solve for x . 4 x = 4 3 + 2 n r4 x = 5 3 + 2 integer x = 4 3 4 + 2 4 n r x = 5 3 4 + 2 4 integer x = 3 + 2 n r x = 5 12 + 2 integer
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This note was uploaded on 12/29/2011 for the course MATH 150 taught by Professor Sturst during the Fall '10 term at SUNY Stony Brook.

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