(Chapter 1: Review) 1.42 Our solutions for ±are: =4²3+2n,or=53+2nninteger()From this point on, it is a matter of Algebra. To find our solutions for x, replace with 4x, and solve for x. 4x=43+2nr4x=53+2integerx=434+24nrx=534+24integerx=3+2nrx=512+2integer
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This note was uploaded on 12/29/2011 for the course MATH 150 taught by Professor Sturst during the Fall '10 term at SUNY Stony Brook.