(Section 2.3: Limits and Infinity I) 2.3.32. 9. When dominance fails us, II. Consider lim x ±² sin x + ³ () sin x . We obtain: lim x ±² sin x + () sin x = lim x ±² ´ sin x sin x (by Sum ID or Unit Circle) = ´ 1. If we had replaced x + ± with x in the argument of sin x + () , we would have obtained: lim x ±² sin x + () sin x = ? ± lim x ±²
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This note was uploaded on 12/29/2011 for the course MATH 150 taught by Professor Sturst during the Fall '10 term at SUNY Stony Brook.