CalcNotes0208-page14

CalcNotes0208-page14 - (Section 2.8: Continuity) 2.8.14 1 ,...

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Unformatted text preview: (Section 2.8: Continuity) 2.8.14 1 , and we require x 0 . x We will find the continuity set for h. We require: Now, let = 2 1 x 2 ( ), and x 0 ( ), and x 0 +nn +nn We can replace both sides of the inequality with their reciprocals, because we already exclude the case x = 0 , and the right side is never 0. 1 x 2 +n ), 1 x 2 x (n (n 2 +n and x 0 ), 2 ( 2 n +2 n ), and x and x 0 0 The continuity set is: x x x x ( 2 n +2 n ( 2 ) 2n + 1 (n ), and x ), and x 0 , or 0. ...
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