ans-M11-1 - 2(A 22.66 m/s(B 12.33 m 3(A – 4.930 – 14.61...

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PHY 2048 Midterm Answers - DAY Fall 2010 1. ( 115 t 2 – 107 t ) N 2. T = F / sin( 2 ) [free-body diagram like Wolfson problem 5-35] 3. 2.291 m [ energy - collision - energy or constant a ] 4. 5.778 s 5. False. It can if F is perpendicular to v, as in circular motion. 6. 67.65 m 7. (A) 7.832 m/s (B) 4.377 m PHY 2048 Midterm Answers - NIGHT Fall 2010 1. 7.696 kg [ standard incline free-body diagrams ]
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Unformatted text preview: 2. (A) 22.66 m/s (B) 12.33 m 3. (A) ( – 4.930 – 14.61 ) m/s (B) 591.7 J $ i $ j 4. 317.9 J from Power = Work / time 5. 12.93 m/s 2 6. True, because F is perpendicular to motion or because KE is constant 7. – 98.22 kJ [ solution must use E f = E i + W ] Note : These are answers, not complete solutions....
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