HW1 - θ is equal to the latitude of the location of the...

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HW1 You know that on a certain day at noon a vertical pole at the equator makes no shadow. Your have a vertical pole 10 meters tall and at noon it throws a shadow of 15cm, plus or minus 1 centimeter. Using the known radius of the earth, how far from the equator are you? What is the uncertainty in that distance? Some clarification. Since you know that a pole at the equator throws no shadow, you know that the day is the equinox; the sun is directly overhead at the equator. From the diagram below, this means that the angle that the sun’s rays make with the pole,
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Unformatted text preview: θ , is equal to the latitude of the location of the pole. So you can find from the shadow, and given the radius of the earth you can find the distance to the equator. Write this distance as a formula involving the measured distance so that you can use the formula given in class 1 to find the uncertainty in the distance, as well as the value. 1 If we have y = f(x) and σ x is the uncertainty in x , then y (the uncertainty is y ) is given by x y x y ∂ ∂ = . The derivative of y with respect to x is the sensitivity of y to fluctuations in x ....
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