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Unformatted text preview: 8 again we find n = ( Î»/2L) Î”m + 1. (b) N = 2L (n-1)/ Î» = 2*0.1 m*(1.00045-1)/589 nm = 153. 4. A form of the Jamin Interferometer is illustrated below. How does it work? To what use might it be put? When the incoming beam hits the first air-glass interface, part is reflected (R1) and part is transmitted (T1). R1 travels through air to the second splitter while T1 reflects off the mirror and reemerges into the air. At the second splitter, part of R1 is passed through the glass, yielding a T2 beam while T1 is reflected to give a R2 beam. This is an amplitude splitter. T2 and R2 are then combined at the observation point. The path lengths of T2 and R2 are the same above, but when a new medium is placed in one arm of the device an interference pattern is produced and can be used to measure the index of refraction. The interferometer can also be used to compare the flatness of one surface to a known optically flat surface....
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This note was uploaded on 12/29/2011 for the course PHYSICS 375 taught by Professor Eno during the Spring '11 term at Maryland.
- Spring '11