{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW6 Sol Phys 375 F09 - Phys 375 HW 6 Fall 2009 Due 16 17...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Phys 375 HW 6 Fall 2009 Due 16 / 17 November, 2009 1. A single slit in an opaque screen 0.10 mm wide is illuminated (in air) by plane waves from a krypton ion laser ( λ 0 = 461.9 nm). If the observing screen is 1.0 m away, determine whether or not the resulting diffraction pattern will be of the far-field variety and then compute the angular width of the central maximum. Solution: Far field condition is given by λ 2 b R > , where R is the distance from slit to observation point and b is the slit width. R=1.0 m, and plugging in the numbers we find: m b 02 . 0 2 = λ . YES, it is far field. From the diffraction formula we know the first zero of intensity is given by b / sin λ θ = . Implying: ( ) 26 . 0 / sin 1 = = b λ θ And the angular width is given by: 52 . 0 2 = θ . 2. What is the relative irradiance of the subsidiary maxima in a three-slit Fraunhofer diffraction pattern? Draw a graph of the irradiance distribution, when the split spacing a = 2 b , where b is the slit width, for 2 and then 3 slits.
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern