Phys 375 HW 2
Fall 2009
Due 21 / 22 September, 2009
1.
Pedrotti
3
, 3
rd
edition, problem 27 (see Fig. 233).
Solution:
See FIGURE 233in the text P
3
From the geometry it is clear that
h
D
C
4
/
tan
, where h is the height of the slab
and D i
s the diameter of the circle of light.
From Snell’s law we know that the critical
angle occurs when the angle of refraction is
2
R
.
Then applying Snell’s Law,
2
2
1
1
sin
sin
n
n
we have:
55
.
1
4
/
4
/
sin
2
/
sin
2
2
h
D
D
n
n
C
air
glass
Where I used
1
air
n
.
2.
Pedrotti
3
, 3
rd
edition, problem 36.
Solution:
See FIGURE 39 of the text P
3
For the deviation angle,
, we have from the figure and equation 39 and 311 :
A
2
1
2
1
2
1
Combining this with equations 3(710), we get:
A
n
A
n
1
1
1
1
sin
sin
sin
sin
Here is a plot of the deviation angle vs. incident angle for n=1.52 and A=60
o
.
40
45
50
55
60
65
39
40
41
42
43
44
45
1
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3.
Write an expression for the
E
 and
B
fields that constitute a plane harmonic wave
traveling in the +
z
direction.
The wave is linearly polarized with its plane of vibration at
45
o
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 Spring '11
 ENO
 Physics, Light, Snell's Law, Sin, Total internal reflection, tan tan

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