Phys 375 Sol HW 2

Phys 375 Sol HW 2 - Phys 375 HW 2 Fall 2009 Due 21 / 22...

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Phys 375 HW 2 Fall 2009 Due 21 / 22 September, 2009 1. Pedrotti 3 , 3 rd edition, problem 2-7 (see Fig. 2-33). Solution: See FIGURE 2-33in the text P 3 From the geometry it is clear that h D C 4 / tan , where h is the height of the slab and D is the diameter of the circle of light. From Snell’s law we know that the critical angle occurs when the angle of refraction is 2 R . Then applying Snell’s Law, 2 2 1 1 sin sin n n we have: 55 . 1 4 / 4 / sin 2 / sin 2 2 h D D n n C air glass Where I used 1 air n . 2. Pedrotti 3 , 3 rd edition, problem 3-6. Solution: See FIGURE 3-9 of the text P 3 For the deviation angle, , we have from the figure and equation 3-9 and 3-11 : A 2 1 2 1 2 1 Combining this with equations 3-(7-10), we get: A n A n 1 1 1 1 sin sin sin sin Here is a plot of the deviation angle vs. incident angle for n=1.52 and A=60 o . 40 45 50 55 60 65 70 39 40 41 42 43 44 45 1
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3. Write an expression for the E - and B -fields that constitute a plane harmonic wave traveling in the +
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This note was uploaded on 12/29/2011 for the course PHYSICS 375 taught by Professor Eno during the Spring '11 term at Maryland.

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Phys 375 Sol HW 2 - Phys 375 HW 2 Fall 2009 Due 21 / 22...

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