{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

hwsol-0401

# hwsol-0401 - HW#1 Solutions ECE 178 WINTER 2004 B.S...

This preview shows pages 1–2. Sign up to view the full content.

HW #1 Solutions ECE 178 WINTER 2004 B.S. Manjunath TAs: Srivatsan Pallavaram, Evan Ruzanski and Christopher Utley Problem 2.2 Brightness adaptation. Problem 2.5 From the geometry of Fig. 2.3, Height of image = height of the lens = 7 mm (given) Focal length (distance of image from lens) = 35 mm (given) Height of object = z mm (say) Distance of object = 500 mm (given) We know by theory of similar triangles applied to Fig. 2.3 that, Height of image / Focal length = Height of object / Distance of object from lens Ö 7 mm / 35 mm = z = 500 mm, or z = 100 mm So the target (object) height is 100 mm on the side. Now, for 1 line on the object we have 1024 elements on the CCD. So the resolution of 1 line is 1024 / 100 = 10 elements/mm. Ö For 1 linepair (lp) the resolution is 5 lp/mm. Problem 2.7 The image in question is given by f(x, y) = i(x, y)r(x, y) = 255 (exp(-[(x-x 0 ) 2 +(y-y 0 ) 2 ] )) (1.0) = 255 (exp(-[(x-x 0 ) 2 +(y-y 0 ) 2 ] )) A cross section of the image is shown in Fig. P2.7(a). If the intensity is quantized using m bits, then we have the situation shown in Fig. P2.7(b), where G = (255 + 1)=2 m .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern