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hwsol-0401 - HW#1 Solutions ECE 178 WINTER 2004 B.S...

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HW #1 Solutions ECE 178 WINTER 2004 B.S. Manjunath TAs: Srivatsan Pallavaram, Evan Ruzanski and Christopher Utley Problem 2.2 Brightness adaptation. Problem 2.5 From the geometry of Fig. 2.3, Height of image = height of the lens = 7 mm (given) Focal length (distance of image from lens) = 35 mm (given) Height of object = z mm (say) Distance of object = 500 mm (given) We know by theory of similar triangles applied to Fig. 2.3 that, Height of image / Focal length = Height of object / Distance of object from lens Ö 7 mm / 35 mm = z = 500 mm, or z = 100 mm So the target (object) height is 100 mm on the side. Now, for 1 line on the object we have 1024 elements on the CCD. So the resolution of 1 line is 1024 / 100 = 10 elements/mm. Ö For 1 linepair (lp) the resolution is 5 lp/mm. Problem 2.7 The image in question is given by f(x, y) = i(x, y)r(x, y) = 255 (exp(-[(x-x 0 ) 2 +(y-y 0 ) 2 ] )) (1.0) = 255 (exp(-[(x-x 0 ) 2 +(y-y 0 ) 2 ] )) A cross section of the image is shown in Fig. P2.7(a). If the intensity is quantized using m bits, then we have the situation shown in Fig. P2.7(b), where G = (255 + 1)=2 m .
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