This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Math 5125 Monday, September 5 Second Homework Solutions 1. Let G be a group with distinct normal subgroups A , B such that | G : A | = | G : B | = 2. (a) Prove that AB = G . (b) Prove that A / A B and B / A B are distinct normal subgroups of G / A B of order 2 and index 2. (c) Deduce that G has at least 3 subgroups of index 2. (a) AB is a subgroup of G which strictly contains A . Since A has index 2 in G , it follows that AB has index 1 in G and so AB = G . (b) Note that A B is a normal subgroup of G because A and B are normal subgroups. By the subgroup correspondence theorem, A / A B and B / A B are normal sub- groups of G / A B , and they are distinct because A and B are distinct. Since A and B have index 2 in G , we see that A / A B and B / A B have index 2 in G / A B . Finally A / A B = AB / B = G / B , which shows that A / A B has order 2, and similarly B / A B has order 2....
View Full Document