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Unformatted text preview: U is free on v , v , we may dene f , f : U F by f ( v ) = f ( v ) = 1 and f ( v ) = f ( v ) = 0. We may extend f , f to the whole of V by dening f ( w ) = f ( w ) = 0 for all w W . Then f f ( v v ) = 1 and f ( v v ) = 0. Applying f f to v v = v v , we deduce that 1 = 0 which is a contradiction and the result is proven....
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This note was uploaded on 01/02/2012 for the course MATH 5125 taught by Professor Palinnell during the Fall '07 term at Virginia Tech.
 Fall '07
 PALinnell
 Algebra, Vector Space

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