{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

probset4_11 - Chemistry 21b Problem set 4 Out 26 January...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Chemistry 21b Problem set # 4 Out: 26 January 2011 Due: 02 February 2011 Problems are worth: 1a=15, 1b=10; 2a=10, 2b=15; 3a=10, 3b=5, 3c=5, 3d=5; 4a-e=5 points each (for 25 points total). 1. A problem about simple symmetric tops. (a.) Prove the moment of inertia formulae for a symmetric top of form A 3 B can be written as: I bardbl = 2 m A (1 - cosθ ) R 2 I = m A (1 - cosθ ) R 2 + m A m B m (1 + 2 cosθ ) R 2 where R is the A-B bond length and θ the A-B-A bond angle. (b.) Treat AsCl 3 as a rigid rotor with transitions as follows: 75 As 35 Cl 3 has its J=4 5 transition at 21,472 MHz and 75 As 37 Cl 3 has its J=5 6 transition at 24,536 MHz. Fom these data calculate the geometry of the molecule, that is, R AsCl and θ ClAsCl . 2. Consider the molecule thioformaldehyde, H 2 CS. a) Using the asymmetric rotor energy level formulae given in Lecture #10 (Table 10.1 on p. 82), calculate the first few ( J =0, 1 and 2) rotational energy levels of the molecule. The rotational constants are A= 291291.641 MHz, B=17699.628 MHz, and C= 16651.83 MHz. Draw an energy level diagram. This molecule is a near-symmetric top. Which one (oblate or prolate)?
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern