7K - Net ID KEY A BiOMG 3310 QUIZ 7a 11/3/10 ethanol + NAD+...

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Net ID KEY A BiOMG 3310 QUIZ 7 a 11/3/10 1. (11 pts) Given this rxn inside a cell at 300K: acetaldehyde + NADH + H + ethanol + NAD + The intracellular conc are: [acetaldehyde] = 0.02mM, [ethanol] = 0.02mM, [NADH] = 0.04mM, [NAD + ] = 0.40mM, pH = 7.0 The half rxns are: acetaldehyde + 2H + + 2e - ethanol E o ' = -0.19V R = 0.0083kJ/mol K and = 96.5kJ/V mol NAD + + H + + 2e - NADH E o ' = -0.32V a. calculate E o ' +0.32V - 0.19V = +0.13V b. calculate G o ' G o' = -nF E o' = -2(96.5kJ/V mol)(0.13V) = -25.1kJ/mol c. calculate G G = G o' + RTln[ethanol][NAD+]/[acetaldehyde][NADH] = -25.1kJ/mol + (2.49kJ/mol)ln(.02)(.40)/(.02)(.04) = -25.1kJ/mol + (2.49kJ/mol)ln(10) = -25.1kJ/mol + 5.7kJ/mol = -19.4kJ/mol 2. (1 pt) Write the overall reaction of glycolysis. No need to show the chemical structures of reactants and products. Glucose + 2NAD+ + 2ADP + 2Pi 2Pyruvate + 2NADH + 2ATP + 2H2O + 2H+ 3. (14 pts) Rxns of glycolysis are shown below, numbered 1 - 10. Glycolytic intermediate molecules are lettered A - L. For (a & b), write the glycolytic intermediate letter(s); for (c - g) the rxn number(s) in the blank. Answers can be used more than once, and some blanks require more than one answer . DRAW THE MISSING INTERMEDIATE, I. molecule letters reaction numbers (a) chemical formula is C 6 (H 2 O) 6 __ A _ (c) oxidation and reduction occur at step(s) _6_ (b) "high energy molecules": _ H, K __ (d) dehydration rxn(s) _ 9 __ (e) rxn(s) are far from equilibrium _ 1, 3, 10 __ (f) isomerization _2, 5, 8_ (g) a product of this rxn is ATP _ 7, 10 __ 4. (4 pts) Circle T(true) or F(false) next to the statements below that apply inside a living cell to metabolic rxns we have studied so far:
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7K - Net ID KEY A BiOMG 3310 QUIZ 7a 11/3/10 ethanol + NAD+...

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