ES1F09 - 9“ 533 Physics 227 - First Common Hour Exam 12...

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Unformatted text preview: 9“ 533 Physics 227 - First Common Hour Exam 12 October 2009 Profs. Rabe and Coleman Your name sticker with exam code SIGNATURE Turn off and put away cell phones now! The exam will last from 9:40 pm to 11:00 pm Use a #2 pencil to make entries on the answer sheet. Enter the following ID information now, before the exam starts. In the section labelled NAME (Last, First, MI.) enter your last name, then fill in the empty circle for a blank, then enter your first name, another blank, and finally your middle initial. Under STUDENT # enter your 9—digit student ID. Enter 227 under COURSE, and your section number (see label above) under SEC. Under CODE enter the exam code given above. During the exam, you may use pencils, a calculator, and one handwritten 8.5 x 11 inch sheet with formulas and notes, with- out attachments. There are 16 multiple—choice questions on the exam. For each question, mark only one answer on the answer sheet. There is no deduction of points for an incorrect answer, so even if you cannot work out the answer to a question, you should make an educated guess. At the ened of the exam, hand in the answer sheet and the cover page. Retain this question paper for future reference and study. questions on the exam. When you are asked to open the exam, make sure that your copy contains all 16 questions. Raise your hand if this is not the case, and a proctor will help you. Also raise your hand during the exam if you have a question. Please SIGN the cover sheet under your name sticker and have your student ID ready to show to the proctor during the exam. Useful information o 2 speed of light 2 3.00 X 108 m/s qe 2 e 2 charge on an, electron 2 —1.602 X 10’19 Coulombs (1p 2 +6 2 charge on a proton 2 +1.602 X 10—19 Coulombs me 2 electron mass 2 9.11 x 10"31 kg m1’ 2 proton mass = 1.67 x 10‘27 kg k = 9.00 x 109Nm2/C’2 60 = 8.85 x 10"12 c2/(Nm2) g 2 9.80 m/s2 16V 2 1.602 x 10‘19 J 1 mC = 1030, luC210‘SC 1 nC = 10-90, 1pC210‘12C xawNVEw 535 f4 :0 0) mm «a: 34m 0% «Gm! MN 5&5“on NEE): f 5 $36 fig S1 3; REE 03553 \Qoécznd wfinim mufikkgxxwts,‘ mu EEES 3 0. vusmmu X93322» 3n.me Gum 85M 0“ iiwé 5 § No.0 no? mi u L momroim: nu yo a a N - hm? u .1hN3‘.‘ :3 <5.“ C: mu 0 US$36... 0W >81 nHCOE “13%,” n3? \ <>‘a> ‘86,an urfifiw wé kg E??? i: 2% $3., 2:5: $80358 waywme m3 m0 muflazm .530 93 go 0330 may 2. $55 .0- mmudgo mmfiawo Hoposwmoo H350 m3 233 0m- $330 mmuamo Hopodwmoo 33:8 93 ,0 @330 8230 855980 6:8. map @2628 mm $330 0.8 95mm 93 E 2.26% 3805980 Eofigmm 335080 ,Bozon $0.33 an? E: A0 m TS x 3% @ $853.8 mg 3. @296 E “6.85 30:5 263 £3.39 93 $0.5m wmznfld E \33 mo mmdflg : .Eom H u @23me d N3 @833me {£50 8.3 we mmpflm 93 mg m H 2 E338 3502me fig Bflggmo SEQ 62.2.3 < ammo 6 2.: 3 3% 3 .m em €93 .832 >003 Q. < am @35wa EB a . .m em 93$ $ng >82 mm < em dmfimmpom 83L 6 .m Swap wwmflg .5sz .8 £952 .m em on .98 < ,mofimmxaoo mo wfiwmmmmw #39 $503 mm m 93 < 503me @38me $3589 mfi mo mwsflswma 39 Au .m av. fig .5ng 32: a. < av. E338 2? 3 .m em 93E $.52 353 B < em E5889 9? cm was: a $53 was B €33 .m 8 < 80¢ Dido- @330 .m $2.58 353 H 35 x83 mmow Ema 2.58% m< A 3 Ah .JHQW6Q mfig HE.\\%{ vxmgiu 3 . hm \6 .L% mfg: mg; , 7.3me wfi so mfi 3+ m5 3% £3 mg no mfi o?on w! map magma :m E. .3073 . 0 $10 m my: w% m v§< ~§$O¢NV umg 50 WNW? g $833de map E 850% mm $m+ .omgfio mfiflmom d 33 nwl Rampage ofifiwmmm a 350.3 was: Eon $5 85832 umma Edamflw £355 .w 5. A flat sheet is in the shape of a rectangle with sides of lengths _ - o ‘2. 0.400 m and 0.600 m; The sheet is immersed in a uniform electric @ ' = 5 0110 N X 5m 7‘ Of/ X 6 Wl field of magnitude {El—430.0 N/C that is directed at 200° from V C the plane of the sheet, as shown in the figure. The magnitude of c A} I qu the electric flux through the sheet is u C a) 17.1 N mg/C b) 0.082 N mZ/C @410 N mZ/C d) 11.3N mZ/o e) 12.0N mZ/C 6. A charge of +6uC is placed at X = +0.01m, y=0, and a charge of -6MC is placed at X = ~0.01n1, y:0. What is the direction of the force on a charge of +3MC located at X=0, y = +0.01n1? a) + i b nne of these gl +AJ' 6) ~J' 7. The radial electric field produced by a certain spherically sym— ) VJ‘ ' a metric charge distribution centered at the origin is given by U 3’6 W55 I Em") : 1573 V/m, @ : Ger/LC <30 . where r is the distance from the origin measured in meters. The total charge contained inside a sphere surrounding the origin of m 2 -F3y’ 5 pkg/Lg afl mat/1U: 2W) ) E = 603/. radius 2 m is: v 4 4 m1 . 3 X ’03 Vm/ m 5322*18‘28 62" “w T“ “' ‘ . X ' ~ 42' ’L 3 ‘C 39m: 60$: C xwgflm 3X/O e 1.4 10-80 _ 'X ) X “2,7 M) c 10. 11. A proton with a velocity of \7 = (1 x 106 m / s)i enters a region with a uniform electric field E = Eoi with E0 = (~2.09 x 10‘2)N/C'. After one second \7 is (—1.00 x iofim/s) i (3.00 x lOGm/s) i c) (—3.67>< 109m/s)i d) (1.00 x 106m/s) i e) (0.00 m/s) i To initiate a fusion reaction, two protons need to be so close that their centers are separated by 1 X 10‘15 m. Assuming the protons to be point charges of magnitude 6, what is the electrical potential energy in this configuration? a) 931 J b) 2.3 x 102 J C 1.6 X 10‘19 J 2.3 X 10‘13 J 6) - 1.44 X 106 J The figures show an electric dipole in an external electric field. Which configuration has the least potential energy? ole—£603 ————-—-—-—-———-—-> \p :1: .__—.———-——-——-——> a) d)E __—..—-—-——-——-——> e)E A parallel—plate vacuum capacitor has 10.0 J of energy stored in it. The separation between the plates is 2.0 min. After the plates are disconnected from the potential source, the plate separation is decreased to 1.0 mm. What is the energy now stored in the capacitor? a) 20J b) 4m 10J / d) 5.0J e 2.5J w“; ~19 *2. A EJF=06E9L602><I0 4,07% My F2474 Z) “Z’Zx/Oémm 710%“; Mkcfibm “>1 E /\ ’ V 52A f ’ZOQ . \/' loam iXZx/Omi/u ' 1 g.“ S s ,4; 7L: 13 2— U= Rel : ‘7x/oc’A/mtx(/«67‘/0“HC) --.’-,;- ’O—gsm CZ m = 2. 3 x/of’ga— U 1‘ is A649)” when [555 “(0V3 E- 90>) Even Wl’y’la‘lf' W3 #fmlfija) out Cm czan W‘s sh‘on as N. Iowebl- L] {J nigh/mad 1/{jdAcfl W‘f’ éhol 1-5 AS 791% {‘0 M W fish/W and 'N vii/La? 1'; U kph/«e /€//;A 0w)” L55 {bl/e. ‘Gl/M’Q C t 2 emf If (3 6130015165 g Q snaffle, SW) (J Cwarz U76 = 5,07 12. Each capacitor shown has a value of 5 ME What is the equivalent capacitance of this A combination? D a) 20 [.LF C1 E C2 b) 0.5 MF E c) 5.0 ,LLF 3 In d 15 MF e) 2.0 [.LF B 13. Which of the following is true? a) Energy cannot be stored in a vacuum. b) The electric field E : Fo/qo measured at a point in space diverges as the test charge go is sent to zero. c) In general, electric field and electric potential are directly proportional to one another. d) Electric fields require a dielectric, and do not develop in a , perfect vacuum. We can think of the energy stored in a parallel plate capac— itor as being stored in the electric field between the plates. 14. A line charge with linear charge density A extends along the X~a;xis from X=a to x=4a as shown in the figure. What is the potential at the origin? 13) girl c) —k>:1ln(4) d) 3% ext/COM)" \ \ + ) + L - l j g f ~— ‘ _. ---F_ «J [Of/1F C81) (O/MF 54F 2/“ a) Tia/3e. Ema-137 am Aer-flayed as e/eJWC fleas. Fol/£6. 71: film damages 4/50, 7Le ymcg I? I2; [MaoWLaE/r {Q be (OPP/hwy. c) False. gz-W ' l ‘ cl) For/5Q. Example "' pain/t Che/gfi M vfiCUL/M. e) The X34101 x:C/Q V(><=o> = k .Mx‘: m M = will X 7<=<L 7”“ 15. Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. A point charge q is placed at the center of the cavity. The magnitude of the electric field at a point outside the shell, a distance 7" > R2 from the center is: d) 71'50(R1 —r2 e) 4711:37‘2 16. A +1OMC charge is placed at x = 0 and a +4OMC is placed at a: = 0.1111. At what point on the m-axis' between the two charges is the electric field equal to zero? a) m = 0.05m 13) m = 0.02m c) ac = 0.025111 d E 7E O everywhere between the two charges. a m = 0.033m Same as If fighfl aim/by CH3 [5 COMWW od’ [ya/Al” («r/’56 l @ka 4/760 W v ...
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ES1F09 - 9“ 533 Physics 227 - First Common Hour Exam 12...

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