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E2F08 - Physics 227 Second Common Hour Exam 12 November...

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Physics 227 - Second Common Hour Exam 12 November 2008 Profs. Rabe and Coleman = Your name sticker with exam code = SIGNATURE Turn off and put away cell phones now! 1. The exam will last from 9:40 pm to 11:00 pm 2. Use a #2 pencil to make entries on the answer sheet. Enter the following ID information now, before the exam starts. 3. In the section labelled NAME (Last, First, M.I.) enter your last name, then fill in the empty circle for a blank, then enter your first name, another blank, and finally your middle initial. 4. Under STUDENT # enter your 9-digit student ID. 5. Enter 227 under COURSE, and your section number (see label above) under SEC. 6. Under CODE enter the exam code given above. 7. During the exam, you may use pencils, a calculator, and one handwritten 8.5 x 11 inch sheet with formulas and notes, with- out attachments. 8. There are 16 multiple-choice questions on the exam. For each question, mark only one answer on the answer sheet. There is o deduction of points for an incorrect answer, so even if you cannot work out the answer to a question, you should make an educated guess. At the ened of the exam, hand in the answer sheet and the cover page. Retain this question paper for future reference and study. questions on the exam. 9. When you are asked to open the exam, make sure that your copy contains all 16 questions. Raise your hand if this is not the case, and a proctor will help you. Also raise your hand during the exam if you have a question. 10. Please SIGN the cover sheet under your name sticker and have your student ID ready to show to the proctor during the exam. Useful information c = speed of light = 3.00 × 10 8 m/s q e = e = charge on an electron = -1.602 × 10 - 19 Coulombs q p = + e = charge on a proton = +1.602 × 10 - 19 Coulombs m e = electron mass = 9 . 11 × 10 - 31 kg m p = proton mass = 1 . 67 × 10 - 27 kg k = 9 . 00 × 10 9 Nm 2 /C 2 ǫ 0 = 8 . 85 × 10 - 12 C 2 /(Nm 2 ) μ 0 = 4 π × 10 - 7 =12 . 57 × 10 - 7 Tm/Ampere g = 9.80 m/s 2 1 eV = 1 . 602 × 10 - 19 J 1 mC = 10 - 3 C, 1
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