L6F11 - P123 F2011 Common Hour Exam 1 Grade Histogram...

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P123 F2011 Common Hour Exam 1 Grade Histogram
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2 P123F11 Lecture 6 7 October 2011 Applying Newton’s Laws of Motion REVIEW OF LAST WEEKS LECTURE Forces: Equilibrium: Newton’s 1 st Law: Newton’s 2 nd Law: Newton’s 3 rd Law: (action-reaction pair) Add vectorially R F F 2 1 i i F F F R ... 2 1 i y i y i x i x F R F R i i F 0 A on B B on A F F 0 Then 0 If a F i i ) constant ( v i i a m F z y x i i ma F z y x , , , , 2 F 1 F R 3 F 2 F 1 F
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3 T w = mg NEWTON’S 1 ST LAW: Important Case: = Static Equilibrium EXAMPLE : A light fixture that weights 20 N is suspended from the kitchen ceiling by a single chain. (massless) • What is the tension in the chain? - Draw a free body diagram for fixture: Equilibrium => Must have a chain that can support a tension of 20 N. const. v o F i i o v ii i y x F F i 0 ; 0 0 i x i F N 20 0 mg T mg T F i y i
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4 T 1 T 2 mg T 2 cos(45 o ) T 2 sin(45 o ) N 14 41 . 1 N 20 ) 707 . 0 ( 2 mg T T 1 cos(45 o ) T 1 sin(45 o ) 45 o 45 o EXAMPLE: Suppose I wish to hang the (20 N) light fixture with two cables at 45 o from vertical. What is
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L6F11 - P123 F2011 Common Hour Exam 1 Grade Histogram...

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