ES3S11 - 1. ln P = ( H / RT) + C ln (P2 / P1) = (H / R)( (1...

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1. ln P = (– Δ H / RT) + C ln (P 2 / P 1 ) = – ( Δ H / R)( (1 / T 2 ) – (1 / T 1 ) ) ln (747 / 760) = – (43.82 kJ / R) ( (1/ T 2 ) – (1/ 390.95 K) ) T 2 = 390.45 K = 117.2°C 2. density = mass of unit cell / volume of unit cell mass of unit cell = number of atoms in a unit cell times mass of one atom mass of one atom = molar mass divided by 6.022 x 10 23 density = 4.62 g/cm 3 = (2atoms)(262 g/mol) / (volume of unit cell)(6.022 x 10 23 atoms/mol) Therefore, volume of unit cell = 1.883 x 10 –22 cm 3 = (edge length) 3 Therefore, edge length = 5.732 x 10 –8 cm. For a body-centered unit cell, edge length = 4 r / (3 1/2 ) , so r = 2.48 x 10 –8 cm = 248 pm. 3. S = k P gas k = S / P gas k = (3.7g/L)(1 mol / 44.01 g) / (2736 Torr)(1 atm / 760 Torr) = 0.023 mol / L atm 4. mass fraction = mass of solute / mass of solution = 0.71 Take 1000 g of solution. This contains 710 g of solute HNO 3 , or 11.27 moles. The volume of solution is (1 mL / 1.42 g)(1000 g) = 704.2 mL. Then molarity = 11.27 moles / 0.7042 L = 16 M. 5. T b = (k b / k f ) T f = (2.53/5.12)( 4.53°C) = 2.24°C T b = 80.10°C + 2.24°C = 82.34°C 6. CaCl 2 Ca 2+ + 2 Cl y – x x 2x fraction dissociated = x/y = 0.785 van’t Hoff factor i = ((y–x)+x+2x)/y = 2.57 π = 2.57(.225M)(R)(303K) = 10930 mmHg 7. (8.0 x 10 –4 mol / 1 L (5.0 sec) )(2 mol NOBr/1 mol Br 2 ) = 3.2 x 10 –4 mol/Lsec 8. Comparing experiment 2 with 1, the initial concentration of B is the same, the initial concentration of A is doubled in experiment 2, and the rate is increased by a factor of 5.44/0.068 = 8. Therefore, rate is proportional to the concentration of A cubed. Comparing experiment 3 with 1, the initial concentration of A is the same, the initial concentration of B is increased by a factor of 24.4 in experiment 1, and the rate is increased by a factor of 0.068/0.028 = 24.4. Therefore, rate is proportional to the concentration of B raised to the first power.
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This note was uploaded on 01/04/2012 for the course CHEMISTRY 160 taught by Professor Petrone during the Spring '08 term at Rutgers.

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ES3S11 - 1. ln P = ( H / RT) + C ln (P2 / P1) = (H / R)( (1...

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