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**Unformatted text preview: **bar appear at the bottom. If the bottom row is all zeros, both left and right of the vertical bar, the system is dependent, meaning infinitely man solutions. If the bottom row has zeros to the left of the vertical bar and nonzero number on the right, it is inconsistent, meaning no solution. Solve the system using row operations to get the augmented matrix in row echelon form: [1] Augmented matrix [2] a 11 = 1 [3] a 21 = 0 1. 5 3 4 4 10 x y x y +-= -= 2. 4 3 4 1 6 4 2 5 2 3 22 x y z x y x y z--= -+ = + + = 3. 2 3 3 2 2 2 5 3 2 x y z x y z x y z-- = + + = + + = Try These: 4. 4 5 3 2 5 2 5 4 3 13 2 2 2 2 w x w x y w x y z w x y z-= -+-= - -+ + = +-- = - 5. 2 3 2 2 6 3 3 5 x y z x y z x y z +- = -+ = -+ =...

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