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Unformatted text preview: 1 = ax 2 + (2a)x + 6 We know that c is the yintercept, which equals 6. 1 = a – 2a + 6 We also know that a must be positive, since the porabola opens 5 = a up. We set the equation equal to 1 because we used the point a = 5 (1,1). 1 replaces all x’s and f(x). Now that we know what a kkkk equals, we can find b. 2a = b (2)(5) = b b = 10 We now have solved for a, b, and c. We can conclude that our k quadratic function is f(x) = 5x 2 10x + 6. To check our work, k we plugged the equation into our calculators. Our graph was kk consistent with all of the information given to us. Jon—graph here...
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This note was uploaded on 01/05/2012 for the course MATH 115 taught by Professor Blakelock during the Fall '08 term at University of Michigan.
 Fall '08
 BLAKELOCK
 Calculus, YIntercept

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