Unformatted text preview: 10 CHAPTER 2. MATHEMATICAL PREREQUISITES
√
√
the following multiples of sin(x) are all normalized: sin(x)/ π , (for α = 0), − sin(x)/ π , (for
√
α = π ), and i sin(x)/ π , (for α = π/2).
Answer: A multiple of sin(x) means c sin(x), where c is some complex constant, so the
magnitude is
2π c sin(x)c sin(x) = c sin(x) = 0 (c sin(x))∗ (c sin(x)) dx You can always write c as ceiα where α is some real angle, and then you get for the norm:
c sin(x) = 2π
0 (ce−iα sin(x)) (ceiα sin(x)) dx = 2π
0 √
c2 sin2 (x) dx = c π √
So for the multiple to be normalized, the magnitude of c must be c = 1/ π , but the angle
α can be arbitrary. 2.3.7 Solution dotg Question: Show that the functions e4iπx and e6iπx are an orthonormal set on the interval
0 ≤ x ≤ 1.
Answer: You need to show that both functions are normalized, e4iπx = 1 and e6iπx = 1,
and that they are mutually orthogonal, e4iπx e6iπx = 0. Work each out in turn (don’t forget
to take complex conjugate of the ﬁrst function in the inner products):
e4iπx  = e4iπx e4iπx = e6iπx  = e6iπx e6iπx = e4iπx e6iπx = 1
0 1
0
1
0 Operators e−6iπx e6iπx dx = e−4iπx e6iπx dx = (Since the Euler formula shows that ei2π = 1.) 2.4 e−4iπx e4iπx dx = 1
0 e2iπx dx = 1
0
1
0 1 dx = 1 1 dx = 1 1 2iπx 1
=0
e
0
2iπ ...
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This note was uploaded on 01/06/2012 for the course PHY 3604 taught by Professor Dr.danielarenas during the Fall '11 term at UNF.
 Fall '11
 Dr.DanielArenas
 mechanics

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