Unformatted text preview: E n with a high value of n to E 2 ? Answer: It is like the previous question, except E n will be approximately zero at high values of n . E n − E 2 = 0 eV + 3 . 4 eV = 3 . 4 eV 1 . 602 10 − 19 J 1 eV = 5 . 45 10 − 19 J Dividing by ¯ h = 1.054 10 − 34 J s gives the angular frequency to be 5.17 10 15 /s, and then the wave length is 364 nm. That will be near ultraviolet. The transition from E 4 will produce bluegreen light, from E 5 indigo, and from E 6 violet. 4.2.4 Discussion of the eigenfunctions 4.2.4.1 Solution hydda Question: At what distance r from the nucleus does the square of the ground state wave function become less than one percent of its value at the nucleus? Express it both as a multiple of the Bohr radius a and in ˚ A....
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This note was uploaded on 01/06/2012 for the course PHY 3604 taught by Professor Dr.danielarenas during the Fall '11 term at UNF.
 Fall '11
 Dr.DanielArenas
 mechanics, Energy, Light

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