Unformatted text preview: 1 2 ω ; 1 2 ωt must be a whole multiple of 2 π for the coe±cients to return to their original values. Answer: The coe±cients are c n (0) e − i (2 n +1) 2 ωt Now if ωt is 2 π , the argument of the exponential equals i times an odd multiple of π . That makes the exponential equal to minus one. It takes until ωt = 4 π until the exponential returns to its original value one. 7.1.2.3 Solution schrodsolc Question: Write the full wave function for a onedimensional harmonic oscillator. Formulae are in chapter 3.6.2. Answer: Using the give formulae Ψ( x, t ) = ∞ s n =0 c n (0) e − i (2 n +1) 2 ωt h n ( x ) 7.1.3 Energy conservation...
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 Fall '11
 Dr.DanielArenas
 mechanics, Light, ωt, 7.1.2.2, 7.1.2.3

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