Analytical Mech Homework Solutions 22

Analytical Mech Homework Solutions 22 - CHAPTER 3...

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CHAPTER 3 OSCILLATIONS 3.1 () [ ] 1 0.002sin 2 512 x stm π  =  ( ) ( ) max 0.002 2 512 6.43 mm x ss  ==   ± ( ) ( ) 22 4 max 0.002 2 512 2.07 10 x × ±± 3.2 0.1sin x t ω = D [ m ] 0.1 cos m xt s ωω = DD ± When t = 0, x = 0 and 0.5 0.1 m x s  D ± 1 5 s = D 2 1.26 Ts D 3.3 cos sin x x tx t t =+ D D ± D and 2 f = D ( )[ ] 0.25cos 20 0.00159sin 20 x tt ππ m 3.4 cos cos cos sin sin α βα β −= + cos cos cos sin sin x AtA t A t φφ φ =− = + D cos sin x , cos A Α = , sin A Β = 3.5 11 2 1111 2222 mx kx mx kx += + 2 12 21 kx x mx x 1 2 x mxx    D 111 222 kA mx kx ± 2 2 x x x Ax x x =
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This note was uploaded on 01/06/2012 for the course PHYSICS 4360C taught by Professor Johnanderson during the Fall '11 term at UNF.

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